Physics Asked by user20250 on June 4, 2021
So, this is how the problem looks:
Plus, the pulley is suspended on a cord at its center and hanging from the ceiling.
You’re given masses of the objects, mass of the pulley and it’s radius. And your assumptions are that the string is massless and inelastic and that there is no friction between the string and the pulley. You have to find the tension in the string suspending the pulley (it’s not drawn in this particular figure).
My conclusion was that, since there is no friction between the string and the pulley, the tension would have to be equal all along the string’s length and the pulley would not rotate, it would slip and there would be no way to transfer the linear motion of the masses to the rotational motion of the pulley. (The resulting torque would be zero.)
So, according to me, the tension in the string suspending the pulley would simply be the tension along the rope multiplied by two.
But the solution includes a rotating pulley and its rotational inertia, and it gives a different answer. Where did I go wrong? And why? If not, how can I prove I’m right?
You're correct that if the pulley is frictionless the pulley wouldn't rotate. Most likely, the authors of the problem had in mind to say “this is an idealized physics problem” and didn't reason correctly about which parts of the system need this specified, or just wrote the wrong words or incorrectly simplified them during editing.
Here are some possible causes of energy dissipation that could be in the system that they arguably should have specified instead:
Answered by Kevin Reid on June 4, 2021
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