Physics Asked on July 5, 2021
I’m working on creating a pool of physics questions for my students, and I came up with one whose solution made me stop and think. I’m not asking for checking/proofing of my work, I think it’s correct. I just want some help/confirmation of my analysis of the results.
The problem has a mass hanging in the corner between a wall and ceiling. It’s held up by two tension forces (as shown in the illustration below). The strings are parallel, making the hypotenuse of a triangle with the wall and ceiling as the legs. The mass is static.
My solution necessitates the mass to be 0kg, so I interpret this as thinking that it’s impossible to hold up a positive mass with two strings in the way presented. The two strings would HAVE TO have at least a slight difference in angle for things to work out. I.e. there’d be a bit of sag in the system to accommodate gravity.
If my thinking is correct, that’s great… but then I think about extending this to a problem where the mass is held up by two rigid beams, not strings. So there, how would one reconcile the need for sag if it’s a rigid structure? Is there still technically sag but on a microscopic level?
I’m going to be teaching this soon, so I just want to make sure I’m brushed up on my reasoning. Thank you for any suggestions!
In practice there would be a sag. The ideal rigid body can also be invoked. Such a body provides whatever forces are required to stop it bending and squashing. In particular, it can provide sheer forces: forces at right angles to the line along which the body may lie. With a rigid strut fixed to the ceiling by a joint which does not even allow the strut to swing, you can support anything at any angle without requiring any further tension forces elsewhere.
Correct answer by Andrew Steane on July 5, 2021
Of cause. there is not really a completely rigid body, so there would be a small displacement. If you calculate with an ideal rigid body, the fastening at ceiling and wall has to take the weight.
Answered by trula on July 5, 2021
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