Isn't Velocity of Electric field a violation of law of conservation of energy?

Let take two positive charges $q_1$ and $q_2$.
There are four points. $q_1$ was initially located at (a), and $q_2$ was at (d). Distance between (a) to
(d) is taken 1 lightsecond. Distance between (b) and (c) is also about 1 lightsecond (but a little less)

(a)…(b)…………….(c)…(d)

$q_1$……………………………$q_2$

$q_1 $is moved from (a) to (b) toward $q_2$, and in a similar way, $q_2$ is moved from (d) to (c) toward $q_1$.
Let say they both were pushed for half a second.
Due to speed of electric field, during the push, $q_1$ and $q_2$ will not feel any change in position of each other. For the force applied during the time of the
push, we assumed that $q_2$ was at (d) for $q_1$, and for $q_2$, $q_1$ was at (a). The confusion here is that the energy transferred that $q_2$ got (as a signal) would be greater than the energy needed to push $q_1$, because for $q_2$, $q_1$ is moved, and the distance between them is less than the distance that of $q_1$ felt during push.

(For Energy given) $text{Force on } q_1 = dfrac{Kq_1q_2}{r^2
}$

(For energy output) $text{Force on } q_2 = dfrac{Kq_1q_2}{r’^2
}$

When we think about $r$, we found that it would be somewhere between distance of (a) – (d) and (b) – (d), as the electric field of $q_2$ will be there the
same for 1 second.
But for $r’$, it is between (a)-(d) and (b) – (c),
so $r>r’$.
Therefore, the force on $q_2$ is greater.

Assume that you are $q_1$ and are pushed for 1/2 second over a very short distance. You will find that field of $q_2$ were the same there for that
time period as a result of the velocity of the electric field. So, the $q_2$ for $q_1$ was at (d) during push.
Thus, $q_1$‘s average distance from $q_2$ was somewhere between (a) – (d) and (b) – (d).

However, for $r’$ taken for force on $q_2$ for receiving signal was different from $r$. Here, I am $q_2$ and was moved at the same time, but when your changed electric field reached me after 1
second, I was also moved closer.
So, for me, you moved closer, and I also moved a little closer to you,
which makes my average distance from $q_1$ less than $r$.