Physics Asked on December 14, 2020
When the magnet, starting with the north pole, goes towards a coil of wire (maybe a solenoid???) the magnetic field within the wire changes polarity in order to repel the north pole. This is so that work has to be done against the magnetic field in order for that work done to be converted into electrical energy.
When the magnet pulls away from the coil (so the south pole is the closest face towards the coil), the polarity of the magnetic field within the coil of wire changes so that the south pole is attracted. Thus work has to be done again to pull the magnet out of the field and thus the work done is converted into electrical energy so an emf is induced.
What I don’t understand about my own explanation is that how can a coil have a magnetic field unless it is a solenoid? And if the coil is a solenoid, then it must already have an emf going through it because a current-carrying coil is used to produce a magnetic field and I don’t know….
I know Faraday’s law explains the magnitude of the emf induced but I’m trying to make sense of the negative (contributed by Lenz) in: induced emf is directly proportional to (-) rate of change of magnetic flux linkage.
I don’t even know if I’m explaining my confusion correctly…
< What I don't understand about my own explanation is that how can a coil have a magnetic field...
It is often ignored that electrons are not only charged particles but they also have a magnetic dipole. Their electric and their magnetic fields are intrinsic - existing independent from the surrounding circumstances - properties.
Moving a permanent magnet inside a coil, the magnetic dipoles of the interacting electrons get aligned. The effect of the spin comes into play. The spin makes the displacement of the electrons and a current starts (as long as the magnetic field changes).
Answered by HolgerFiedler on December 14, 2020
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