TransWikia.com

Is there a special name for this vector field?

Physics Asked on March 28, 2021

The gravitational field of a point mass can be shown to be solenoidal (i.e. its divergence is zero) at all points except where the point mass actually is. This implies that there exists a vector field $vec{F}$ whose curl is the point mass’s gravitational field. I know in magnetostatics, due to Gauss’s law for magnetism (i.e. $vec{nabla}cdotvec{B}=0)$, there exists a (not necessarily unique) vector field $vec{A}$ called the magnetic vector potential such that $vec{nabla}times{vec{A}}=vec{B}$. My question is: is there a similar name for that vector field $vec{F}$ such that $vec{nabla}times{vec{F}}=vec{g}$, where $vec{g}$ is the gravitational field? And how come I don’t think I ever really see this vector field get used? I mean, since the gravitational field of a point mass is also irrotational everywhere (except where the point mass is), it is quite common to be using a scalar field $Phi$ called the gravitational potential such that $-vec{nabla}Phi=vec{g}$.

2 Answers

The gravitational field is not a solenoidal field. See the definition. The difference between the magnetic field and the gravitational field is that the magnetic field is source-free everywhere, while the gravitational field (just like the electric field) ist only source-free almost everywhere. While this might seem a minor difference, it is actually of topological relevance: the magnetic field lines are closed (they do not end at a source), while the gravitational and electric field lines begin and end at sources.

Of course you can represent the gravitational field (just like the electric field) locally (i.e. in a compact, simply connected region that does not contain sources) by a curl even though it is not a solenoidal field. But for what purpose? That might be the reason why you don't see it: because there is no use case for it.

Correct answer by oliver on March 28, 2021

In order to describe any vector field, you need to know its divergence and curl in order to have it uniquely determined. When we are dealing with gravitational field $$ vec{g}=-Gmfrac{vec{r}-vec{r}'}{|vec{r}-vec{r}'|^3} $$ One can find that its divergence is $$ nabla·vec{g}=-4pi Grho_m $$ This divergence is $4pi Grho_m$ at mass sources and $0$ everywhere else. You can check this by calculating divergence in spherical coordinates and by integrating it over a sphere of constant radius.

Its curl, though, is exactly equal to zero (check it!) and that is precisely the reason why we can write the field as the gradient of a potential function $$ nablatimesvec{g}=0 to vec{g}=-nablaphi $$ This kind of fields are called conservative or irrotational. Thus, we have the field completely defined by its divergence and curl.

Answered by Rafael Rodríguez Velasco on March 28, 2021

Add your own answers!

Ask a Question

Get help from others!

© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP