Physics Asked by Luna Sage on January 23, 2021
If we have two current-free spaces and separated by a surface current, we can solve the magnetic problem by solving two magnetic scalar potentials and then using matching conditions. My question is, is the general scalar magnetic potential continuous? Why?
A potential is essentially an integral of work to carry a particle (magnetic or electric one) from an infinite distance up to the point you need to know the potential value. If the force making the work is not a Dirac's Delta, then the integral (i.e. the potential) must be a continuous function.
Answered by JoeCoolman on January 23, 2021
The potential for a static magnetic problem is defined through $$ {bf B} = - nabla phi $$ (or you can define another potential for $bf H$). Then since $nabla cdot {bf B} = 0$ we have Laplace's equation for $phi$ and that is why it is useful: we have lots of good methods for solving Laplace's equation. (Of course it won't work if $nabla times {bf B} ne 0$; in that case one should adopt another approach.)
The above equation implies that the answer to your question is that $phi$ is continuous if and only if $bf B$ is finite. At a boundary such as a surface you expect to find finite $bf B$. At a current-carrying wire of arbitarily small radius, on the other hand, $bf B$ can diverge.
Answered by Andrew Steane on January 23, 2021
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