Is an accelerating velocity the same as an identical non-accelerating velocity?

I’m referring to an instant in time where the velocities of two different particles are identical. One particle experiences a force and the other does not. I think their states of motion are different even if the velocities are identical. Am I correct?

The state of motion of an object is defined by its velocity. See the following:

https://www.physicsclassroom.com/class/newtlaws/Lesson-1/State-of-Motion#:~:text=The%20state%20of%20motion%20of,resist%20changes%20in%20its%20velocity.&text=Such%20an%20object%20will%20not,upon%20by%20an%20unbalanced%20force.

Based on that definition, if the velocities of the two particles at an instant in time are the same, their state of motion is the same. A change in velocity is therefore a change in state of motion. If you are only told the instantaneous velocity of two particles is the same you have no way of knowing what, if any, forces are acting on the particles.

I have no problem with your statements for Figures 1 and 2. But I'm having trouble following your last paragraph. For example, the first sentence of the last paragraph seems to contradict the first sentence of the prior paragraph.

I believe you need to further clarify the last paragraph to enable a complete answer to your post.

In any case, to the extent possible, hope this helps.

in the moment, both particles have the same velocity it is of cause the same, for example if both were cars of the same mass they would cause the same damage in a collision. What is different is not the velocity, but the acceleration. So if you compare at the same moment and in in this moment the acceleration stops both continue with 10mps.But for many people the idea of a velocity in a moment is hard to grasp, if the velocity is changing continuously, since you could not measure it, to me measure a velocity, you have to have an interval of time.

The key to showing why they behave the same is calculus.

You are correct that a particle cannot simultaneously have a force on it and no forces on it, just due to sheer logic. However, what we can say is that the particle can have a force on it at some time point $t$ (such as when the two objects are at the same velocity), and no force on it at some time $t + dt$, where $dt$ is some infinitesimally small duration of time.

Infinitesimals are a pest. Its really easy to try to make sense of them one way and then find that you generated a contradiction (such as having a force and no force at the same time). They gave us trouble for thousands of years. Newton and Leibnitz's calculus is the tool we use to resolve them. It was the first method of calculating using infinitesimals which didn't generate horrible contradictions.

Using calculus, we can see that the two ball's states are equal after the time t except that one had a force applied to it for the infinitesimal amount of time between $t$ and $t+dt$. When you run math using calculus, you find that the effect of applying a finite force for an infinitesimal amount of time is 0. So thus, if ball $A$ is traveling at $v_a$, ball $B$ is traveling at $v_a + 0$, which of course equals $v_a$. That little infinitesimal difference doesn't matter once you integrate it.

Indeed, the astonishing beauty of calculus is that it can handle these individual, isolated infinitesimal differences and say "they have 0 effect," and yet not write yourself into a corner where you're forced to say "because I can split up any motion into infinitesimally small pieces, and infinitesimally small pieces have no effect, there is no motion." This would be Zeno's most famous paradox. The precise wording of calculus lets us resolve this paradox.

Now there's two caveats to this which are probably useful going forward.

• Practically speaking, you can't stop applying a force instantaneously. No practical device is capable of going from a finite force to zero force instantaneously. So when your intuition says there's something different between $A$ and $B$, you're right. This perfect equality only exists in the mathematically exact corner case that you are investigating.
• When you get further into physics, you'll learn about Lagrangian formulations of motion. In this, there is one formula for a system, called the Lagrangian, which never changes for the system, and all particles are defined using just their position and velocity. The fact that we were able to define the physics of all systems using only position and velocity, bundling up any forces into that one unchanging equation, is probably one of the more fascinating things I've come across in physics. We can define Lagrangians with higher order terms, like accelerations, but it turns out that, in our universe, we don't actually need them.