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Interpretation of the photon scattering rate?

Physics Asked by faber on December 10, 2020

The photon scattering rate $Gamma$ describes the rate at which photons scatter off an atom$^1$. In a two-level system, the ansatz for the photon scattering rate often is given by

begin{equation}
Gamma = rho_{22}gamma
end{equation}

where $rho_{22}$ is the probability to find the atom in the excited state and $gamma$ is the rate of spontaneous decay. However, I don’t see the connection between the ansatz above and what the photon scattering rate is physically meant to be.


$^1$In my imagination, the photon scattering rate is the absorption rate for photons at a certain frequency $omega$. Hence $Gamma(omega)$ shows the saturation broadened Lorentzian absorption line of the atom, centered around a resonance frequency.

One Answer

Considering light as a stream of photons at energy hω, photon scattering is usually defined as cycles of absorption and subsequent spontaneous emission.

$$Γsc(r) = Pabs /hω = 1 /he0c*Im(α) I(r).$$

http://cds.cern.ch/record/380296/files/9902072.pdf

The photon scattering rate is the radiated power divided by the photon energy hω.

$$Rsc = Prad /ω$$

http://atomoptics-nas.uoregon.edu/~dsteck/teaching/quantum-optics/quantum-optics-notes.pdf

Answered by Árpád Szendrei on December 10, 2020

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