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if I drop a mass into a black hole, will the black hole's gravity be asymmetrical before the mass reaches the singularity?

Physics Asked by Wolphram jonny on April 20, 2021

The question is in the title, so basically you drop a mass into a non rotating black hole, and then the distribution of mass inside the black hole will not be spherically symmetric (assume the mass did not reach the singularity yet). Will this information affect the gravitational field surrounding the black hole outside the horizon? or will this field be always spherically symmetric?

My confusion is that we cannot know anything from inside the horizon (other than total mass), but an asymmetric distribution of matter should result in an asymmetric gravitational field. So what is wrong in my reasoning?

One Answer

As the falling object approaches the horizon from outside, the situation is already not spherically symmetric so neither is the spacetime. In a reference frame in which the object passes the horizon in a finite time, the spacetime outside remains non-spherically symmetric after the object passes the horizon, though the asymmetry will be dynamic and will tend to radiate away until eventually the whole thing settles to a symmetric shape (in the absence of angular momentum). At all times the spacetime at any given place is influenced only by matter and signals which can arrive there, in the future light cone of other events. So it is not influenced by events beyond the horizon.

Correct answer by Andrew Steane on April 20, 2021

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