How much of a difference does it make whether you blow on hot soup indoor vs outdoor?

Question

How much of a difference does it make whether you blow on your soup to cool it down while in your dining room versus if you open the outside door in the winter and blow on it that way?
This would help settle the argument I'm having with my wife every time she does this. I'm not good enough at physics/math to calculate the answer myself.
some details:

You have 300 ml of hot soup, heated to 90 degrees celsius
the air temperature in your dining room is 25 degrees celsius
the outside temperature is 5 degrees celsius
your body temperature is 36.5 degrees celsius
the temperature of your exhaled breath, while you are in the dining room, is about 35°C and 95% humid
I'm guessing that when you open the window you are breathing in the air that is half influenced by the room temperature, and half by the outside cold (let's say 15 degrees celsius)
the temperature of your exhaled breath, while you are blowing out of an open window, is unknown to me, but can be calculated
you open the window and blow on your soup for 40 seconds

How much sense does your action make? :)

Gert · Accepted Answer

Because your body temperature isn't dependent on room/outside temperature this has no effect on cooling rate.
But temperature of the surroundings (of the soup), that is outdoor or dining room, has a strong bearing on convection losses. Newton's Law of Cooling basically states that a 'hot' object loses heat at a rate $dot{Q}$ ($mathrm{J/s}$) that is directly proportional to the difference in temperature between the 'hot' object and its 'colder' surroundings $Delta T$ ($^circ mathrm{C}$):
$$|dot{Q}|propto Delta T$$
So the soup will cool down faster in the colder outdoors, compared to the warmer dining room.

How much of a difference does it make whether you blow on hot soup indoor vs outdoor?

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