How does Normal reaction work to provide Centrifugal force in a banked road when some of force due to gravity is already there?

Question

I came across the problem-

A turn of radius 20m is banked for the vehicles going at a speed 36km/hr. If the coefficient of static friction between road and the is 0.4, what are the possible speeds of a vehicle so that it neither slips down or skids up?

While solving it, I come across resolving forces along the road as frictional force, sine of force due to gravity and also Sine of Normal Reaction force which just complicates the solution

What is the way to solve this question as the solution I have just says ignore normal reaction and then solve the question, and it works. How? I mean if Normal reaction is giving the force, why is it not in the Free Body Diagram?

Anusha · Answer

Normal actions is assumed to be absent because we consider that the frictional force is just enough to ensure car moves in a circular path and a limiting case that contact of car is just broken with road is taken I.e N=0

Answered by Anusha on April 5, 2021

How does Normal reaction work to provide Centrifugal force in a banked road when some of force due to gravity is already there?

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