Physics Asked by Krish Vasa on March 4, 2021
I saw a video of Walter Lewin on YouTube in which he was showing a demonstration on Capacitors. In this demonstration, he gives a charge to the Capacitor, dissembles it and reconstructs the Capacitor. But after removing the charges also, the Capacitor still holds a potential difference. How is that possible?
The demonstration starts at 39:00
In a dielectric induced charges only exist in the presence of an electric field. So, when you disassemble the capacitor all induced charge was supposed to disappear. And it does if you apply low voltage to the capacitor. However, in the demonstration of the video you provide a high voltage is applied to the capacitor and corona discharge pumps free charge into the dielectric (not explained in your video). This free charge is not easily removed from the glass and remains there for the whole experiment. When you assemble the capacitor again, it is that free charge that passes from the glass to the conductors that gives rise to the spark. The experiment is made possible by combining materials with different dielectric strengths and high voltage to induce corona discharge from the metal to the dielectric (through air) but not inside the dielectric.
The detailed explanation of this is given in the video below starting at 32:30:
https://www.youtube.com/watch?v=By2ogrSwgVo&list=PLyQSN7X0ro2314mKyUiOILaOC2hk6Pc3j&index=16
Correct answer by Blue on March 4, 2021
It's clear from the video that all the charges left the conducting plates, but the induced charges on the dielectric still remains which maintains a potential difference. This video will be extremely helpful for an intuitive understanding of what's actually happening when we charge a capacitor.
Answered by user243016 on March 4, 2021
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