Heat equation, $Q=msdtT$ during fusion and vaporization

Question

We know that the heat supplied is directly proportional to the change in temperature. But during fusion and vaporization, the temperature is the same i.e $d T=0$. Is the equation invalid in these process?

electronpusher · Answer

You are correct. There is instead a substance-specific "enthalpy of fusion" to account for the heat gained/lost during the constant-temperature phase change.

Heat equation, $Q=msdtT$ during fusion and vaporization

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