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Gravitational Field Strength of a point in between Two Planets

Physics Asked on December 24, 2020

In my textbook, under the topic of gravitation, it states that if the centres of 2 planets, each of mass $M$ and separated by a distance $r$ and you have a point halfway between the centres of the planets, the gravitational field strength at that point is $0$.

I don’t fully understand why that is. Is it because the point feels an equal force in each direction so the resultant gravitational force is $0$, resulting in $0$ gravitational field strength at that point?

Surely however gravitational field strength is a measure of how many Newtons of gravitational force a body feels per kg. In this case, shouldn’t it be equal to
$$2times frac{GM}{(0.5r)^2}=frac{8GM}{r^2}$$
as it feels
$frac{GM}{(0.5r)^2}$ Newtons of force from 2 planets?

One Answer

You are correct. The two forces are in opposite directions and cancel each other.

Force is a vector quantity. When adding vectors the directions are as important as the magnitudes.

Perhaps you are confusing gravitational field strength $g=GM/r^2$ and gravitational potential $V=-GM/r$. The former is gravitational force per unit mass, so like force it is a vector. When adding field strength you use vector addition (eg the parallelogram rule). The latter is the work done in moving a unit mass from infinity to a point at distance $r$ from the mass $M$, so like work it is a scalar. When adding potentials due to several masses you do so algebraically, regardless of the direction of the mass which is creating the potential.

Correct answer by sammy gerbil on December 24, 2020

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