Geostationary Satellite

I am unable to understand one particular thing about geostationary satellite. Let us assume that I am on earth at a particular place and remain there (moving with the place during rotation) such that the satellite is just above me all the time.

Now my orbital velocity will be

$$ v_o = sqrt{GM_e/R_e} $$

Talking about the geostationary satellite at a height $h$ we can say that the orbital velocity is

$$ v_{geo} = sqrt{GM_e/(R_e+h) } $$

This showa that the velocity of the satellite has decreased and simultaneously its radius has increased.

But it must have my angular velocity to have the same time period.

$omega =v/r$

For the satellite $v$ has decreased and $r $ has increased. How can the angular velocity of satellite be equal to that of mine.