Physics Asked by pasaba por aqui on January 1, 2021
An answer to the question When is the Hamiltonian of a system not equal to its total energy? is:
In an ideal, holonomic and monogenic system (the usual one in classical mechanics), Hamiltonian equals total energy when and only when both the constraint and Lagrangian are time-independent and generalized potential is absent.
(from Siyuan Ren (https://physics.stackexchange.com/users/3887/siyuan-ren), URL (version: 2011-07-06): https://physics.stackexchange.com/a/11918/ )
that seems the most exact one I’ve found in several similar posted questions.
I’m trying to translate these conditions to equations.
The function $h$ defined by the equation $$h=sum_jleft( frac{partial mathcal{L}}{partial dot{q}_j}dot{q}_jright)-mathcal{L}$$ is called the energy function of the system $mathcal{S}$.
If $mathcal{L}=mathcal{L}(q,dot{q},t)$, then $partial mathcal{L}/partial tnot=0$ and $h$ is not conserved.
If $mathcal{L}=mathcal{L}(q,dot{q})$ then $partial mathcal{L}/partial t =0$ so that $h$ is a constant. The conservation formula $$sum_jleft( frac{partial mathcal{L}}{partial dot{q}_j}dot{q}_jright)-mathcal{L}=mathrm{constant}$$ is called the energy integral of the system $mathcal{S}$.
If $mathcal{S}$ is a conservative standard system, then $mathcal{S}$ is autonomous and so $h$ is conserved. In addition, energy integral can be written in a more familiar form, if
$$T=sum_{j,k}a_{jk}(q)dot{q}_jdot{q}_k$$
and $V=V(q)$. The energy integral becomes $$h=T+V=mathrm{constant}$$ In this case the total energy $E$ of the system.
Now All you need to do is to take Hamiltonian in place of the Energy function. $$mathcal{H}=sum_jleft( frac{partial mathcal{L}}{partial dot{q}_j}dot{q}_jright)-mathcal{L}=sum_j p_jdot{q}_j-mathcal{L}$$
Answered by Young Kindaichi on January 1, 2021
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