Physics Asked on January 12, 2021
I am trying to find continuous function $sigma(x)$ for uniform intensity.
I set two parallel horizontal lines with length $W$ and with distance each other $H$.
The upper line is a target plane section, below one is a LED plane.
Intuitively, the $sigma(x)$ will have next propeties
I calculated intensity using $I(r,theta) = I_0 A_0frac{1}{r^2} cos^m(theta) = I_0 A_0 H^m((x-t)^2 +H^2)^{-{(m/2 +1)}}$.
On one point of $t$, the intensity can be calculated as
$$I(t, sigma) = I_0 A_0 H^m int_{-frac{W}{2}}^{frac{W}{2}} sigma(x) ((x-t)^2 +H^2)^{-{(m/2 +1)}} dx$$
and the average value is
$$I_{avg}(sigma) =I_0 A_0 H^m int_{-frac{W}{2}}^{frac{W}{2}} int_{-frac{W}{2}}^{frac{W}{2}} sigma(x) ((x-t)^2 +H^2)^{-{(m/2 +1)}} dx dt $$
Therefore, the variance of intensity will be
$$V(sigma) =frac{1}{W} int_{-frac{W}{2}}^{frac{W}{2}} (I(t,sigma) – I_{avg}(sigma))^2 dt $$
The optimized function $sigma_{opt}$ will make it a minimum.
$$V(sigma_{opt}) = V_{min}$$
If I use variation method, I think it will be
$$frac{partial V}{partial sigma} = int_{-frac{W}{2}}^{frac{W}{2}} 2 (I-I_{avg})frac{partial }{partial sigma} (I-I_{avg}) dt$$
It is work that I did and I stuck. I think the calculus of variations methods will be helpful. However, I am not familiar to work with such a multi-integrated function. (I am a sophomore undergraduate student in physics major.)
On last equation,
$$frac{partial }{partial sigma} (I-I_{avg})$$
The $I-I_{avg}$ is a functional with integral, so I think I cannot just calculate it as usual Lagrangian.
So my question is " Is it possible to find such function $sigma $ by derivative of functional? "
Additionally, are there other approachs to find such $sigma$?
One thing I worried about is it is impossible to solve, actually, I searched some papers in optics about arrange LED sources and they using computational algorithms approaches not the work I did.
p.s
I am considering using numerical solution with assumption $sigma(x) = sum a_n x^{2n}$
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