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Euler angles - geometry

Physics Asked on January 31, 2021

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Hello, I don’t quite see why should the angle between $hat{dot{theta}}$ and the projection of $hat{dot{phi}}$ onto the $x_0$, $y_0$ plane be a right angle. Does it have something to do with pure geometry or physics? Of course it gives the right answer for the angular velocity as a function of the Euler angles, but I don’t see why it is necessarily a right angle.

One Answer

They don't have to be, but convention has it that consecutive rotations in Euler angle schemes be orthogonal to each other.

The orientation is set by a sequence of three rotations, each being perpendicular to the previous rotation such that the influence of one angle to all the other rotations is zero.

And since the sequence $mathrm{R} = mathrm{R}_z mathrm{R}_x mathrm{R}_y$ consists of three mutually orthogonal rotations, the resulting rotational speed is a sequence of mutually orthogonal relative rotations

$$ vec{omega} = hat{z}_0 dot{psi} + mathrm{R}_z left( hat{x}_1 dot{theta} + mathrm{R}_x (hat{y}_2 dot{phi}) right) $$

In this case, $hat{z}_0$ is perpendicular to $mathrm{R}_z hat{x}_1$, since $hat{z}_0$ is perpendicular to $hat{x}_0$ and the rotation $mathrm{R}_z$ does not change that. Also, $hat{x}_1$ is perpendicular to $mathrm{R}_x hat{y}_2$, since $hat{x}_1$ is perpendicular to $hat{y}_1$ and the rotation $mathrm{R}_x$ does not change that also.

Answered by John Alexiou on January 31, 2021

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