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Error in thermal time constant from measurement

Physics Asked by JNV on August 19, 2021

I would like to know how to calculate the error in thermal time constant ($tau$) based on temperature measurements. For example, lets say I have a plate with a thermocouple and I provide it with a step input. The step power input will cause a $1$st order temperature change at the location of the thermocouple.

The temperature at time $t$ is
$$
T(t) = T_s + (T_i – T_s) e^{-t/tau}.
$$

where $T_s$ the static-state (equilibrium) temperature, $T_i$ the initial temperature.

At $t=tau$, we have $$T(tau) = T_s + frac{T_i – T_s}{e}$$
I can find the temperature at time $tau$ and from the temperature vs time measurement data I can determine the time constant $tau$ ($T_i$ and $T_s$ are both not $0 C/K$).

If my thermocouple has a fixed error of lets say $pm 1 C$, then what would be the error in the derived time constant, $tau$?

Thanks for your help in advance!

One Answer

From $ T(t) = T_s + (T_i - T_s) e^{-t/tau}$ you can express $tau$: $$ t rm{ln} big[frac {T_i - T_s}{T(t) - T_s}big] = tau. $$ For small errors in temperature measurements you can write this as $t rm{ln} big[frac {T_i +delta T_i - T_s - delta T_s}{T(t)+delta T - T_s-delta T_s}big] = tau +deltatau$ and can expand to first order as $$delta tau/t approx frac {1}{(T_i - T_s)} delta T_i - frac {1}{T(t) - T_s} delta T +big(frac {1}{T_s - T_i}+frac{1}{T_s-T(t)}big) delta T_s $$ To a first order with independent (uncorrelated) measurement errors in the quantities $T_i,T_s, T(t)$, the error variance estimate is then $$sigma_{tau}^2 /t^2 approx frac {1}{(T_i - T_s)^2} delta (T_i)^2 + frac {1}{(T(t) - T_s)^2} (delta T)^2 +big(frac {1}{T_s - T_i}+frac{1}{T_s-T(t)}big)^2 (delta T_s)^2 $$

Answered by hyportnex on August 19, 2021

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