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Entropy change for molecular nitrogen

Physics Asked on January 3, 2021

Calculate specific entropy change for $N_2$ from 250 K and 1000 kPa to 1300 K and 60 kPa using $Delta s=phi_2-phi_1-Rln (frac{p_2}{p_1})$ given that $phi_1=6.6587 kJ/kg/K$ and $phi_2=8.4604 kJ/kg/K$.

My question is what the physical meaning of $phi_1$ and $phi_2$ is.

2 Answers

In this notation, $phi$ is the temperature part of the entropy, while the last term in the equation is the pressure part.

Answered by snike on January 3, 2021

$ Deltaphi = int_1^2 frac{c_p}{T}dT $

Answered by hyportnex on January 3, 2021

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