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Energy and Momentum conservation, what else?

Physics Asked on March 17, 2021

Note: there is no friction at all.

General problem:
A ball moves (in speed v1) toward a quarter of a circle (which was stand still before the ball touched it and can move on x) and walks on it until it leaves it.
How may I find the balls speed on x and y?

I have attached the following image to make the problem easier:

enter image description here

In this kind of questions, we use save of energy and save of linear momentum on x.

Using save of energy gives me the value of the ball’s speed But How may I get the speed on x direction and y direction of the ball?

Using save of momentum gives me an expression with two variables, the ball’s speed on x and the mass’s speed on x. (Which doesn’t help since I don’t know both of them)

Am I missing something here?

One Answer

When the ball exits from the top, the ball's speed in $x$ and the ramps speed are the same. Because just before exiting, the ball was in contact with the ramp. If it was slower, the ball wouldn't be in contact, whereas if it was faster, the ramp would deform. This will eliminate one variable and permit you to solve the two equations.

Answered by dnaik on March 17, 2021

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