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Eigenfunction of a wave function with boundary condition

Physics Asked by karla.tr on January 13, 2021

I read a paper about boundary conditions and imaginary potentials. In this paper the author considers a single, non-relativistic quantum particle of mass $m > 0$ in $1$ dimension with a soft detector in finite interval $[0,L]$, $L>0$, with Schrödinger equation
begin{equation}
ihbar frac{partialpsi}{partial t} = – frac{hbar^2}{2m}frac{partial^2 psi}{partial x^2}- iv Theta(x)psi(x)
end{equation}

where $v>0$ is a constant and $Theta(x)=1$ for $xgeq 0$ and $0$ otherwise. At $L>0$ he considers the Neumann boundary condition $frac{partial psi_t}{partial x}(L)=0$.

The author writes, that for $x<0$, being an eigenfunction of $-(hbar^2/2m)partial^2/partial x^2$ means to solve an ODE in $x$, whose general solution has the form
begin{equation}
f(x)=d_k e^{ikx}+c_ke^{-ikx},.
end{equation}

My question is: How did he find this eigenfunction and how do you compute an eigenfunction of a wave function with boundary condition?

One Answer

A solution in the form of plane wave superposition $d_k e^{i k x} + c_k e^{-i k x}$ is a standard solution always used to solve ODEs. To see this, you should refer to the first paper where it was ever used. I don' t know what it is. The point is that exponential solutions work.

If you want some interpretation, my personal one is that using plane waves means going into the frequencyu (Fourier) space, where derivatives become products. But this is just some interpretation, practically when you solve differential equations, the first soultion you look for always is in the form of $e^{i k x}$.

Answered by SoterX on January 13, 2021

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