Physics Asked on May 12, 2021
My understanding of Euler-Bernoulli (EB) equation is that it is the energy balance equation in Lagrangian form for an inviscid, incompressible and steady-state flow . From different sources I see different equations attempting towards extending the equation for compressible or viscous flows. For example the wikipedia entry for the matter offers:
$$v dv+frac{dP}{rho}=0 tag{1}$$
along the stream for compressible flow (assuming there is no body force i.e. gravity) and I have also seen:
$$v dv+ dh=0 tag{2}$$
also along the stream for viscous flows (which paradoxically does not include viscosity).
If my understanding of the EB equation is correct then we must be able to drive them from Eulerian form of continuum equation of energy balance neglecting conduction and radiation:
$$
left{
begin{matrix}
rho left( check{v} check{nabla}^T right) e=check{sigma} : check{nabla}^T check{v}
left( check{v} check{nabla}^T right) left( h+frac{v^2}{2} right)=0
end{matrix}right. tag{3}$$
Where
$$ check{sigma}= check{tau} -Pcheck{I} tag{4}$$
and
$$check{tau}=etaleft(
check{nabla}^T check{v}+
left(
check{nabla}^T check{v}
right)^T
right)
+lambda
left(check{nabla}check{v}^Tright)
check{I} tag{5}$$
For Newtonian fluids.
So my questions are:
I think the equation(s) you are looking for are in table 11.4-1 of BSL. You will be dealing with basically two types of energy balance: overall energy balance and mechanical energy balance. The overall energy balance is basically the 1st law of thermodynamics, and the mechanical energy balance is basically the equation of motion dotted with the velocity vector. These equations each contain some common information and some separate information, and can be coupled to yield other forms of energy equation. The coupled form (or forms) you choose depends on which one works best for the problem you are solving at that time.
Your question about enthalpy relates to all this. Eqn. 1 is a steady state simplified version of the equation of motion dotted with the velocity vector. Eqn. 2 is a simplified version of the overall energy balance for steady state approximately adiabatic reversible flow. For the latter, $dh=TdS+vdP=vdP=frac{dP}{rho}$
Answered by Chet Miller on May 12, 2021
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