TransWikia.com

Density of free particle energy eigenfunctions in 1d for periodic boundary conditions

Physics Asked on August 4, 2021

The energy spectrum for the above, subject to the periodic boundary conditions such that the eigenfunctions are have a period of $L$, is given by
$$E_n = E_0n^2, qquad n=0, pm1, pm2, ldots$$
where $E_0 = (2pi^2hbar^2)/(mL^2)$. Each $Eneq0$ is doubly degenerate.

Then to find the density of states, I observe that $E_{n+1}-E_n = E_0(2n+1)approx 2E_0n=2sqrt{E_0E_n}$. Since there’s double degeneracy, I conclude that the energy density at energy $E$ is
$$frac{2}{2sqrt{E_0E}}=sqrt{frac{m}{2E}}frac{L}{pihbar}.$$

But Merzbacher in his Quantum Mechanics says that it should be
$$sqrt{frac{2m}{E}}frac{L}{pihbar}.$$

Where did I go wrong?

Add your own answers!

Ask a Question

Get help from others!

© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP