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Confusion about Fourier's Law

Physics Asked on August 18, 2021

According to the textbook I am reading (Fundamentals of Heat and Mass Transfer by Incropera), Fourier’s law of thermal conduction, $q_x=-kAfrac{dT}{dx}$, is a law based on experimental evidence, not one that’s derived from first principles. The book goes on to describe the experiment that the law is based on. A rod has length $Delta x$, cross-sectional area $A$, and its end faces have a temperature difference of $Delta T$. Holding $Delta T$ and $Delta x$ constant, we find that the heat conduction rate $q_x$ is directly proportional to the cross-sectional area $A$. Holding $Delta T$ and $A$ constant, we find that $q_x$ is inversely proportional to the rod length $Delta x$. Finally, holding $Delta x$ and $A$ constant, we find that $q_x$ is directly proportional to the temperature difference between the rod’s end faces, $Delta T$. All of these results can be packed into the proportionality $q_xpropto Afrac{Delta T}{Delta x}$.

The problem I have with this is that the textbook only specifies that there is a temperature difference $Delta T$ between the ends of the rod. It doesn’t specify how the temperature varies between the ends of the rod is. Is it linear? If so, does the relation $q_xpropto Afrac{Delta T}{Delta x}$ only hold for a rod that has a linear temperature variation along its length?

This is just a guess but, maybe the text is implying that, since the temperature will vary linearly over infinitesimal lengths as you take the limit as $Delta x$ goes to zero, we can just apply Fourier’s law for every infinitesimal length along the rod and integrate?

One Answer

If you've chosen to move from $q_x=-kAfrac{dT}{dx}$ for an infinitesimal element to $q_xpropto Afrac{Delta T}{Delta x}$ everywhere for a finite region (in other words, if you've chosen to replace a derivative with a finite difference), then yes, you've implicitly assumed that the slope is constant throughout the rod.

This replacement wouldn't work if the material or conditions were notably heterogeneous or if another heat transfer mode pertained (i.e., if the rod were made of two materials joined at their ends or if an internal heat source existed or if lateral convection or radiation were nonnegligible from the sides of the rod).

In turn, we must avoid any of these complications if we wish to measure the material property $k$ based on applying a temperature difference to a rod and measuring the resulting heat flux. Does this make sense?

Answered by Chemomechanics on August 18, 2021

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