Circular motion of an object on the floor of equator

Question

Object A is located on the floor at the equator.
Is that the magnitude of the normal force on A equal to its weight?
How to obtain an expression for normal reaction in terms of $m,g,r$ and $omega$?

R.W. Bird · Answer

The normal force from the floor (or the reading on a scale) would be N where: mg - N = mR$ω^2$.  The, R, and,  ω, are the radius and angular velocity of the earth.

Circular motion of an object on the floor of equator

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