Chemical potential in semiconductor derivation

Question

In deriving the density of electrons at the bottom of the valence band in a semiconductor,
$$n(T) = int^infty_{epsilon_C} frac{g_c(epsilon)}{e^{beta(epsilon - mu)}+1}$$
we approximate the integral as
$$n(T) = int^infty_{epsilon_C} frac{g_c(epsilon)}{e^{beta(epsilon - mu)}}$$
i.e. $$e^{beta(epsilon - mu)} >> 1$$
because that the chemical potential is far below the minimum conduction band energy $epsilon_C$.
This derivation has reminded me that I never really got to grips with the chemical potential. What is the significance of the chemical potential in this context? Is it simply $mu(T=0) = epsilon_F$ or is there more to it? More generally, I'd love to hear a good way to think about the chemical potential, especially in the context of solid state physics.

boyfarrell · Accepted Answer

I have always found this very difficult to get an intuitive understanding of, this is the way I think about it.
The chemical potential is the energy at which you can add or remove a particle from the semiconductor without changing the entropy of the electron gas.
$$mu_e = left(frac{partial E}{partial N_e} right)_{S}$$
Why? Because of the Exclusion principle.
An electronic gas is a Fermi gas. It has a macrostate with entropy $S$ and temperature $T$ defined by its arrangement of microstates.
For example, if you insert a particle at energy $E$, the ensemble must arrange itself; particles above the energy will all be moved upwards. In general this alteration will have an associated entropy change. The chemical potential is the energy at which there is no entropy penalty to do this.
I would be very interested to hear other peoples intuitive explanations, I’m sure what I’ve written here is not the full story.

Chemical potential in semiconductor derivation

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