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Bragg-Williams theory of phase transition

Physics Asked by kia1996 on January 1, 2021

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Hi I am currently studying Bragg wiliam theory and I dont understand how they derive the equations f(T,m). Actually i dont understand how they got S/N given by equation 8. Can someone explain?

One Answer

Well, as usual the entropy is the logarithm of the number of microstates. If the total number of spins is $N$ and there are $N_{rm up}$ "$+$ spins", then this corresponds to a total number of possible configurations given by $frac{N!}{N_{rm up}!(N-N_{rm up})!} = {}^NC_{N_{rm up}}$ (the number of ways of choosing which of the $N$ spins are "$+$ spins"). This is exactly the first identity in (8).

The second identity in (8) follows from the fact that the magnetization density is $$ m= frac{N_{rm up} - N_{rm down}}{N} = frac{2 N_{rm up} - N}{N} = 2 frac{N_{rm up}}{N} - 1, $$ so that $$ N_{rm up} = frac{(1+m)N}{2}. $$ Of course, this way of computing the entropy totally ignores the fact that the different configurations do not have the same energy, which is why the Bragg-Williams theory only provides an approximation.

Then, they go on getting another approximation, this time for the energy, writing $$ E = -Jsum_{langle i,j rangle} sigma_isigma_j approx -Jsum_{langle i,j rangle} m^2 = -frac12 JNz m^2, $$ since there are $frac12 N z$ pairs of nearest neighbors.

Once they have the (approximate) entropy and energy, they compute the free energy by the usual thermodynamic relation.

Correct answer by Yvan Velenik on January 1, 2021

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