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Are Hamilton’s equations time-independent from it’s general derivation?

Physics Asked by qubitz on March 17, 2021

The general derivation of Hamilton’s equations involve the change in the Hamiltonian and consequently the change in the Lagrangian that is a function of $q$ and $dot q$, $L(q,dot q)$. This is shown in this simple video
https://www.youtube.com/watch?v=jXu6zIItnLM

When deriving Hamilton’s equations for $dot q$ and $dot p$, the Lagrangian is only a function of $q$ and $dot q$ but not time. Therefore the Lagrangian used to derive Hamilton’s equations is time-independent as it appears. Does that means that Hamilton’s equations for $dot q$ and $dot p$ are only right for systems for which the Lagrangian is time-independent (and therefore the Hamiltonian – or energy is conserved)?

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