Physics Asked on January 23, 2021
Thank you all for so much help as I work through Zee’s QFT book. Here I finally have a question about physics instead of math.
Zee makes several comments that the main thing left to do in QFT is find a way to solve
$$ Z(J)=int!Dvarphi,exp!left[ iint!d^4x,frac{1}{2}big[ (partialvarphi)^2-m^2varphi^2 big] -frac{lambda}{4!}varphi^4+Jvarphi right] .$$
Since we cannot solve it directly, even by the magical process for "discretizing and undiscretizing" infinite dimensional path integrals, Zee makes a study of two simplifed cases. He presents a "baby problem"
$$ Z_B(J)=int_{-infty}^infty!dq,exp!left[ -frac{1}{2}m^2q^2-frac{lambda}{4!}q^4+Jq right], $$
and a "child problem"
begin{align*}
Z_C(J)&=int_{-infty}^inftyint_{-infty}^inftydotsint_{-infty}^infty!dq_1,dq_2,dots dq_N,exp!left[ -frac{1}{2},qcdot Acdot q-frac{lambda}{4!}q^4+Jcdot q right]
&=iintdotsint!dq_1,dq_2,dots dq_N,exp!left[ -frac{1}{2}sum_{m,n=1}^N q_m A_{mn} q_n-frac{lambda}{4!}sum_{k=1}^N q_k^4+sum_{l=1}^N J_l q_l right].
end{align*}
Analytically, I see the difference is that $J$ and $varphi$ are functions of a continuous variable in $Z$, a discrete variable in $Z_C$, and they are not functions of anything in $Z_B$.
Q1: What would be the physical significances of $Z_B$ and $Z_C$ respectively?
Q2: What does it mean for $q$ not to be a function of anything?
For $q$ to be a function of a discrete variable, I see that $q$ describes, essentially, the vertical displacement position of a set of oscillators located at some number of discrete $vec x_k$. If it’s not a function of anything, does that mean it is a single oscillator? How could it not be a function of time at least? Is the location of the single oscillator coded into $q$ itself so $q$ means "the oscillator at some $vec x_0$?" If you can go into detail about the physics we are looking at here, that would be very helpful.
Q1: What would be the physical significances of ?? and ?? respectively?
$Z_B$ doesn't really have a physical meaning in the sense of representing an interesting physical system. It is a mathematical toy problem that is easier to think about than the full path integral. If you really want to assign a physical meaning to it, it would amount to integrating over the value of a field at one point in spacetime.
$Z_C$ could represent any number of different systems, really. You can think of it as a general form of a discretized lattice representation of a quantum field theory of an interacting scalar field. In 0+1 dimensions, this could represent the position of a particle in a potential like $V(x)=m^2 x^2 + lambda x^4$ (identifying $phi$ with $x$). The variable $q$ would be identified with the position of the particle and the index would represent time. In 3+1 dimensions, this could represent a discretized version of a scalar field theory. In this case the value of $q$ represents the value of the scalar field, and the index represents different pionts in spacetime.
The full path integral is a continuum limit of $Z_C$, and exactly what field theory you get (how many dimensions, etc) will depend on how the lattice is constructed and how the limit is taken.
Q2: What does it mean for ? not to be a function of anything?
I wouldn't get too hung up on this. I think the 0-dimensional baby problem is just that, a baby problem that's easy to get your head around, but is not a very good model of an interesting physical system.
Correct answer by Andrew on January 23, 2021
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