MathOverflow Asked by Aryeh Kontorovich on November 5, 2020
Under what conditions on a metric space $X$, equipped with the Borel $sigma$-algebra, does there exist a measurable total ordering of the elements of $X$?
By "measurable total ordering" we mean that any initial segment $I_y:={x: x<y}$ is Borel-measurable.
Edit: We know that separability is sufficient for a measurable total order to exist.
Edit II: Vladimir Pestov (private communication) has shown that a measurable total order always exists; will post answer soon with link to full paper.
As mentioned in the OP, Vladimir Pestov has answered the question affirmatively. See Appendix D here: https://arxiv.org/pdf/1906.09855.pdf
Correct answer by Aryeh Kontorovich on November 5, 2020
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