MathOverflow Asked on November 3, 2021
Consider a family of flabby (= flasque) sheaves $(mathcal F_i)_{iin I}$ of abelian groups on the topological space $X$.
My question : is their direct sum sheaf $mathcal F=oplus _{iin I} mathcal F_i$ also flabby?
Here is the difficulty:
Given an open subset $Usubset X$ a section $sin Gamma(U,mathcal F)$ consists in a collection of sections $s_iin Gamma(U,mathcal F_i)$ subject to the condition that for any $xin U$ there exists a neighbourhood $xin Vsubset U$ on which almost all $s_ivert V in Gamma(V,mathcal F_i)$ are zero.
Now, every $s_i$ certainly extends to a section $S_iin Gamma(X,mathcal F_i)$ by the flabbiness of $mathcal F_i$.
The problem is that I see no reason why the collection $(S_i)_{iin I}$ should be a section in $Gamma(X,oplus _{iin I} mathcal F_i)$, since I see no reason why every point in $X$ should have a neighbourhood $W$ on which almost all the restrictions $S_ivert W$ are zero.
Of course any direct sum of flabby sheaves is flabby if the space $X$ is noetherian, since in that case we have $Gamma(U,mathcal F) =oplus_{iin I} Gamma(U,mathcal F_i)$ for all open subsets $Usubset X$.
I have only seen the fact that direct sums of flabby sheaves are flabby (correctly) used on noetherian spaces, actually schemes, so that my question originates just from idle curiosity…
No, a direct sum of flabby sheaves need not be flabby.
Take $X={1,1/2,1/3,1/4,dots}cup{0}$ with the subspace topology from $mathbb R$, and let $mathcal F$ be the sheaf whose sections over an open $Usubseteq X$ are the functions $Utomathbb F_2$ (not necessarily continuous). This is a flabby sheaf. I claim that the infinite direct sum $mathcal F^{oplusmathbb N}$ of countably many copies of $mathcal F$ is not flabby.
To see this, let $U=Xsetminus{0}$, and for $iinmathbb N$ let $s_icolon Utomathbb F_2$ denote the function sending $1/i$ to $1$ and all other elements of $U$ to $0$. Thus each $s_i$ is a section of $mathcal F$ over $U$. Observe that $s=(s_i)_{iinmathbb N}inGamma(U,mathcal F^{oplusmathbb N})$, since locally on $U$ all but finitely many of the sections $s_i$ are equal to zero (the topology on $U$ is discrete).
I claim that this section $s$ doesn't extend to a section of $mathcal F^{oplusmathbb N}$ over all of $X$. Indeed, if $s$ extended to a section $tilde s=(tilde s_i)_{iinmathbb N}$, then there would be a neighbourhood of $0$ in $X$ on which all but finitely many of the $tilde s_i$ were equal to $0$. But this would imply that $tilde s_i(1/i)=s_i(1/i)=0$ for all sufficiently large $i$, which is impossible. Thus $s$ does not extend.
Answered by Alexander Betts on November 3, 2021
Get help from others!
Recent Answers
Recent Questions
© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP