# What is the radius of convergence of $a_n$ where $a_{n+1}=frac{n-5}{n+1}a_n$?

Mathematics Asked by Lucas on July 28, 2020

Consider a sequence $${a_n}$$ which satisfies
$$a_{n+1}=frac{n-5}{n+1}a_n$$

What is the radius of convergence of $$sum _n a_n x^n$$?

Clearly, $$a_n=0$$ for all $$ngeq 6$$.

Assuming you start at $$n=0$$ with $$a_{0}=kinmathbb{R}$$, your sum is the polynomial $$k-5kx+10kx^{2}-10kx^{3}+5kx^{4}-kx^{5}$$ which "converges" for all $$xin mathbb{R}$$ (Convergence barely makes sense here, since it is clearly finite for each $$xinmathbb{R}$$). Therefore the radius of convergence is $$infty$$.

Correct answer by André Armatowski on July 28, 2020

That is correct, and so the series is actually a polynomial. Thus the radius of convergence is $$infty$$, that is the "series" converges for $$|x| (all $$x$$)

Although this is an overkill, one can also use the formula for the radius of convergence:

$$R=frac{1}{limsup_nsqrt[n]{|a_n|}}=frac{1}{0}=infty$$

Not surprisingly we get the same.

Answered by Oliver Diaz on July 28, 2020