Mathematics Asked on December 20, 2021
Let $fin L^1(mathbb{R}),$
then its translation defined by $f(t,x):=f(x+t)$ belongs to $C([0,T];L^1(mathbb{R})).$
In addition if $fin BV(mathbb{R}),$ then
begin{eqnarray}
intlimits_{mathbb{R}} |f(x+t_1)-f(x+t_2)|dx &=& sumlimits_{imathbb{Z}}intlimits_{j=|t_1-t_2|i}^{|t_1-t_2|(i+1)}|f(x+t_1)-f(x+t_2)|dx\
&=&sumlimits_{iin mathbb{Z}}intlimits_{0}^{|t_1-t_2|}|f(x+j|t_1-t_2|)-f(x+(j+1)|t_1-t_2|)|dx\
&leq& |t_1-t_2|TV(f)
end{eqnarray}
which means if $fin BV$ then the function $f(t,x)$ has Lipschitz time continuity..
I have the following doubts?
Is $fin BV$ a necessary condition for Lipschitz time continuity? if not how to weaken the $BV$ condition to get the same result?
Suppose $f$ is not a BV function, under some conditions on $f$, is it possible to show $f(t,cdot)$ is Holder time continuous ? if so what is that condition?
Since $$ frac{1}{|t_1-t_2|}int_{mathbb{R}} |f(x+t_1) - f(x+t_2)|,mathrm{d}x = int_{mathbb{R}} frac{|f(x+(t_1-t_2)) - f(x)|}{|t_1-t_2|},mathrm{d}x $$ a way to rephrase your question is:
When $α = 1$, however, as in your first question, it seems $BV$ is optimal (see Eq. (37.1) in An Introduction to Sobolev Spaces and Interpolation Spaces by L. Tartar) and one has $$ N(f)<∞ iff f ∈ BV. $$
Answered by LL 3.14 on December 20, 2021
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