Mathematics Asked by Luyw on November 26, 2020
I am playing a game where I can gain xp from crafting certain things using some material. The xp is given by$$E=250a+375b+500c$$
$a$ represents how many sets of $50$ of the material I will put in, $b$ of $75$ units, and $c$ of $100$ units. Thus, the total quantity I am putting is
$$Q=50a+75b+100c$$
This is divisible by $25$, so I know that if the quantity I have is $Q’=25q+r$, then I will work with $Q=Q’-r$.
It can be seen that $E=5Q$ for any choice of $a$, $b$, and $c$ that satisfies the $Q$ equation.
Given $Q$, how can I find $(a,b,c)$ that satisfy $Q=50a+75b+100c$?
Presumably you are asking for solutions in nonnegative integers. As pointed out by Morgan Rodgers in their comment, you can set $Q=25S$ and $(a,b,c)=(25u,25v,25w)$ and solve $S=2u+3v+4w$.
Note that $S$ and $v$ are either both even or both odd. If $S$ is even, then write $S=2T$ and $v=2x$ and solve $T = u+3x+2w$; if $S$ is odd, then write $S=2T+3$ and $v=2x+1$ and solve $T=u+3x+2w$.
In either case, you can choose any values for $x$ and $w$ such that $3x+2y le T$, and then $u=T-3x-2y$ is valid and uniquely determined.
Correct answer by Greg Martin on November 26, 2020
Get help from others!
Recent Answers
Recent Questions
© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP