Mathematics Asked on January 8, 2021
Suppose $mathbf{u},mathbf{v},mathbf{w}$ are noncollinear points $inmathbb{R}^2$. Let $mathbf{x} in mathbb{R}^2$. Show that we can write $mathbf{x}$ uniquely in the form $mathbf{x} = rmathbf{u}+smathbf{v}+tmathbf{w}$ where $r+s+t=1$.
Textbook (Shifrin’s Multivariable Mathematics) hint (paraphrased):
$mathbf{w}-mathbf{u} nparallel mathbf{v}-mathbf{u}$ so, $begin{bmatrix} mathbf{w}-mathbf{u}, mathbf{v}-mathbf{u}end{bmatrix}$ is an invertible $2times2$ matrix.
Attempt:
Let $mathbf{A} = begin{bmatrix} mathbf{w}-mathbf{u}, mathbf{v}-mathbf{u}end{bmatrix}, mathbf{c} = mathbf{A}^{-1} cdot mathbf{x}$.
$$
begin{align}
mathbf{x} &= mathbf{A}(mathbf{A}^{-1}mathbf{x}) \
&= mathbf{A}cdotmathbf{c} \
&= (mathbf{w}-mathbf{u})times c_1 + (mathbf{v}-mathbf{u})times c_2 \
&= c_1mathbf{w} + (-c_1-c_2)mathbf{u} + c_2mathbf{v}
end{align}
$$
Regrettably, $c_1 + (-c_1-c_2) + c_2 = 0 neq 1$.
Questions:
Note that for any $x$ there is a unique $c$ such that $x-u = c_1 (w-u)+c_2(v-u)$.
In other words, $x = c_1 w + c_2 v + (1-c_1-c_2) u$.
Correct answer by copper.hat on January 8, 2021
You've found a representation of $mathbf x$ where the coefficients of $mathbf u, mathbf v, mathbf w$ add to $0$. That doesn't do everything you want, but it is a good first step.
Can you find a representation of $mathbf 0$ in which the coefficients of $mathbf u, mathbf v, mathbf w$ add to $1$? If so, then you could combine those, and get a representation of $mathbf x + mathbf 0$ in which the coefficients add to $0+1$.
Answered by Misha Lavrov on January 8, 2021
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