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Laurent series example

Mathematics Asked by Exzone on February 13, 2021

I have been trying to understand Laurent series expansion in complex analysis and I need someone’s confirmation that what I’m doing is right.

Expand the function $f(z) = frac{1}{5-2(z+frac{1}{z})}$ on a disk $frac{1}{2} < |z| < 2$.

My approach was to break this fraction onto smaller parts using partial fractions and I got the following:
$frac{-z}{(z-2)(z+2)} = frac{-1}{2z-4}-frac{1}{2z+4}$

Next thing I think I should do is find Laurent expansion for first fraction on $frac{1}{2} < |z|$ and then $|z| <2$. After that I would do same for second fraction and finally I would have two expansions of this function, one on $frac{1}{2} < |z|$ and second one on $|z| <2$.

Is this the right approach? This has been confusing me a lot lately. Thanks for any tips in advance.

One Answer

The global approach is correct and that's how I would do it. But your computations concerning the given function are wrong. In fact, we have$$frac1{5-2(z+1/z)}=frac1{3(2z-1)}-frac2{3(z-2)}.$$

Correct answer by José Carlos Santos on February 13, 2021

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