If $int_0^{10} g(x),dx = 8$, what is $int_0^{10} [g(x)+2],dx$?

Consider the function $g$ that is continuous on the interval $[−10, 10]$ and that $int_0^{10}g(x)dx=8$. What is $int_0^{10}[g(x)+2]dx$ equal to?

So I tried just substituting the first function to get $8+2$ to equal $10$, but that’s wrong. I really don’t know how to proceed from here.