Mathematics Asked by Ayoub Rossi on March 10, 2021
Suppose I have $mathbb{Z}/24mathbb{Z}$ and $I = {0, 3, 6, 9, 12, 15, 18, 21}$.
$I$ is a principal ideal.
Is there a method to find ALL the generators ?
Thanks in advance !
Hands-on approach: We know that the order of $ain G$ an element equals the order of the ideal it generates. In this case, $|I| = 8$, so $I = (a) iff ncdot abmod 24 neq 0$ for $n = 1,dots,7$.
Since elements of $I$ are of the form $mcdot 3$, this is looking for $m = 1,dots,7$ such that $ncdot m bmod 8 neq 0$ for $n = 1,dots,7$:
$$ncdot m bmod 8 = 0 iff (n,m) in {(4,2),(2,4),(4,4),(6,4),(4,6)}$$
So $6,12,18$ don't generate $I$, and $3,9,15,21$ generate it.
Correct answer by Daniel Plácido on March 10, 2021
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