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How to adjust the base for a super-exponential function?

Mathematics Asked by Utku Sirin on December 13, 2021

I have the following function:

$$
T(i) = (sum_{k=0}^{i/2} sum_{j=0}^k binom k j mu^j lambda^k ) C
$$

where $C$ is a constant. This function is diverging for certain values of $mu$ and $lambda$ (such as $mu = lambda = 0.75$), and converging for certain other values (such as $mu = lambda = 0.5$). I can see that by simulating the function for different values of $mu$ and $lambda$.

My question is whether and how I could calculate the lowest $mu$, $lambda$, or $mu times lambda$ value that would make this function diverging, or the highest $mu$, $lambda$, or $mu times lambda$ that would make this function converging.

Thanks so much!

Regards,

Utku

One Answer

$$T(i)=Csum_{k=0}^{i/2}sum_{j=0}^{k} {k choose j} mu^{j} lambda^{k}=Csum_{k=0}^{i/2} (1+mu)^k lambda^{k}=Cfrac{lambda(1+mu)^{i/2+1}-1}{lambda(1+mu)-1}.$$

Does this help you?

Answered by Z Ahmed on December 13, 2021

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