Mathematics Asked by Newman on January 1, 2021
I’m looking for concrete examples of a countable Bernstein set and an uncountable Bernstein set. I haven’t been able to find or construct any specific examples so far.
Bernstein sets are non-measurable, so there are no concrete examples: assuming the existence of an inaccessible cardinal, it is consistent with $mathsf{ZF}$ that all subsets of the reals are measurable.
All Borel sets are measurable, so there cannot be a countable Bernstein set.
Correct answer by Brian M. Scott on January 1, 2021
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