Example of a cocommutative, non-unimodular Hopf algebra?

1. Definitions: Unimodularity and cocommutativity
Let $H$ be a Hopf algebra over a field $mathbb k$.

• We call $H$ unimodular if the space of left integrals $I_l(H)$ is equal to the space of right integrals $I_r(H)$.
• We call $H$ cocommutative if $tau_{H,H} circ Delta = Delta$. Here, $Delta$ denotes the coproduct of $H$, while $tau: H otimes H rightarrow H otimes H; v otimes w mapsto w otimes v$ is the twist map.

2. Question

• In my lecture notes it says that there are cocommutative, non-unimodular Hopf algebras. What would be an example?

• Apparently, an example is given in Hopf algebras and their action on rings by Susan Montgomery. However, due to the pandemic I am unable to get it from the library. If you have a copy and could write down the relevant section, that would be very much appreciated.

3. My ideas so far

• The Taft-Hopf algebra $H$ over a field $mathbb k$ is not an example:
  If $H$ is commutative (i.e. root of unity $zeta =1_{mathbb k}$), then $H$ is unimodular. In this case, it is even isomorphic to the boring group algebra of the zero group. Otherwise, $H$ is not cocommutative (even though it is non-unimodular then). Non-cocommutativity follows easily from the observation that the square of the antipode is not the identity (if $zeta neq 1_{mathbb k} $).

• Group algebras:
  As the coproduct of a group algebra is given by the diagonal map any group algebra is cocommutative. However, any group algebra $mathbb k[G]$ over a finite group $G$ is unimodular, since
  $$I_l=I_r=mathbb k cdot sumlimits_{gin G} g$$ What about infinite groups?

• Regarding the universal enveloping algebra, tensor algebra, symmetric algebra, alternating algebra I am not sure. What can be said here?

• Maybe the following proposition turns out to be useful: A finite dimensional Hopf algebra $H$ is unimodular iff its distinguished group-like element/modular element $a in G(H^*)$ is equal to the counit $epsilon_H$. Here, the modular element $a$ is the unique linear form such that $tcdot h = t a(h)$ for all $hin H, tin I_l(H)$. It exists because $tcdot h in I_l(H)$ and $I_l(H)$ is one dimensional. It can be shown to be a morphism of algebras, hence a group-like element in $H^*$.