Mathematics Asked by Hazim on November 1, 2021
Given a set A of vectors, is there a minimum number of vectors in A to guarantee that a particular vector b is in span(A)?
If we have a m x n
matrix A – what is the difference between the column space and the span? Everywhere I read makes it seem like they both equal the same thing.
What I understand:
Col(A) is the span of the columns of A – thus Col(A) must have n
vectors in it, since A is of size m x n
. What differentiates this from the span(A)?
Also:
Given a set A of vectors, is there a minimum number of vectors in A to guarantee that a particular vector b is in span(A)?
Shouldn’t A be of R$^n$ once again since there are n columns?
The notation $operatorname{span}(X)$ should be used for a set $Xsubseteq V$ that is contained in some vector space $V$. It is then defined as the intersection of all subspaces of $V$ containing $X$ or equivalently as the set of all linear combinations of elements from $X$.
Writing "$operatorname{span}(A)$" when $A$ is a matrix, doesn't make any sense in terms of this definition. However, it might be an abuse of notation to denote the span of the set of columns of $A$, that is, the column space of $A$. This space is usually denoted $operatorname{col}(A)$ though.
The question about a "minimum number of vectors in a set $X$ to guarantee $binoperatorname{span}(X)$" is unclear to me. For example in the plane $V=mathbb R^2$ you can take the infinite set $$ X = left{ begin{bmatrix} 1 \ 0 end{bmatrix}, begin{bmatrix} 2 \ 0 end{bmatrix}, begin{bmatrix} 3 \ 0 end{bmatrix}, begin{bmatrix} 4 \ 0 end{bmatrix}, dots right} $$ with span $$ operatorname{span}(X) = left{ begin{bmatrix} x \ 0 end{bmatrix} ,middle|, xinmathbb R,right} $$ the does not contain $b=begin{bmatrix}0 \ 1end{bmatrix}$ despite $X$ having infinitely many elements.
Answered by Christoph on November 1, 2021
For example
Let A= begin{bmatrix} 1 &0 &0&0\ 0& 1 &0&1\ 0 &0& 1&1\ end{bmatrix}.
Here $Col(A)= mathbb{R}^3$ and observe that last column in A is sum of 2nd and 3rd columns.
Note that $Span(A)=Col(A)=Row(A)$
Answered by Kumar on November 1, 2021
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