Mathematica Asked by Mattia Landoni on April 20, 2021
If I run the following code:
Do[
Print["*** ", HoldForm[x] /. x -> a, " ***"];
Print["Replace: ", (HoldForm[x] /. x -> a) /. {n1 -> 1, n2 -> 2, n3 -> 3}];
Print["FullForm: ", FullForm[a]];
, {a, {n1 n2, -n1 n2, n1 n2 n3}}
]
I get
*** n1 n2 *** Replace: 1 x 2 FullForm: Times[n1,n2] *** -n1 n2 *** Replace: -2 FullForm: Times[-1,n1,n2] *** n1 n2 n3 *** Replace: 2 x 3 FullForm: Times[n1,n2,n3]
I kind of understand what is going on, but I would like the output in the second case to be -1 x 2
and in the third case 1 x 2 x 3
. How do I do that?
It is enough to write the substitution rule as
{n1 -> HoldForm[1], n2 -> 2, n3 -> 3}
If later one wants the expression evaluated, it will be enough to use HoldForm[]
twice.
Answered by Mattia Landoni on April 20, 2021
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