save a mathematica expression with Root[] as Python expression?

I want to convert a Mathematica expression that uses Root[] to Python (open to using sympy if needed). The expression is:

Root[-k2 k4 N0 + (B0 k2 k3 + A0 k1 k4 + k2 k4 - k2 k3 N0 - 
      k1 k4 N0) #1 + (A0 k1 k3 + B0 k1 k3 + k2 k3 + k1 k4 - 
      k1 k3 N0) #1^2 + k1 k3 #1^3 &, 3]

since FortranForm is close to Python, I could use that and manually edit the expression. But first the Root needs to be substituted. I tried using ToRadicals

ToRadicals[
  Root[-k2 k4 N0 + (B0 k2 k3 + A0 k1 k4 + k2 k4 - k2 k3 N0 - 
        k1 k4 N0) #1 + (A0 k1 k3 + B0 k1 k3 + k2 k3 + k1 k4 - 
        k1 k3 N0) #1^2 + k1 k3 #1^3 &, 3]] // FortranForm

which gives a long expression:

 -(A0*k1*k3 + B0*k1*k3 + k2*k3 + k1*k4 - k1*k3*N0)/(3.*k1*k3) + 
     -  ((1 - (0,1)*Sqrt(3))*(-(A0*k1*k3 + B0*k1*k3 + k2*k3 + k1*k4 - k1*k3*N0)**2 + 3*k1*k3*(B0*k2*k3 + A0*k1*k4 + k2*k4 - k2*k3*N0 - k1*k4*N0)))...

but what does (0,1)*Sqrt(3) mean in FortranForm and what’s the correct way to write it in Python? is it just 1j*sqrt(3)? Thanks.