Mathematica Asked by John Matis on March 20, 2021
Let’s suppose that we want to use random guessing to find a matrix G that satisfies the relation F=G.{x,y}:
F={x+y}
Do[If[F == RandomInteger[{-1, 1}, {1, 2}].{x, y},
Print[RandomInteger[{-1, 1}, {1, 2}]]], 100]
Is there any way to print the random matrix that satisfies the If-condition inside a Do-loop, because every next call of RandomInteger changes the matrix? Sorry for my type style, first time here.
You should generate random pair once per each loop. E.g.
F = {x + y};
Do[If[F == # . {x, y}, Print[#]] &[
RandomInteger[{-1, 1}, {1, 2}]], 100]
or, in a more traditional way:
F = {x + y};
Do[pair = RandomInteger[{-1, 1}, {1, 2}];
If[F == pair . {x, y}, Print[pair]], 100]
Correct answer by Roma Lee on March 20, 2021
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