Mathematica Asked by SJA on December 18, 2020
How do I visualize $exp(z)$ as a complex mapping? How can I ensure that it does not miss any value on the complex plane as it’s value (is in the best condition of Picard’s theorem). Can anyone help me?
You could use ComplexContourPlot
for visualising the real and imaginary axes on the complex z
plane under the complex exponential mapping Exp[z]
.
Define function for complex mapping:
f[z_] := Exp[z]
Then use ComplexContourPlot
for visualising the contours:
Edit: Contours
and ContourLabels
added to ComplexContourPlot
following Michael E2 comment. This shows more clearly that the same lines are displayed in both contour plots.
{ComplexContourPlot[ReIm[z], {z, -3 - 3 I, 3 + 3 I}, PlotLabel -> z,
Contours -> {Range[-2, 2]}, ContourLabels -> All],
ComplexContourPlot[ReIm[f[z]], {z, -3 - 3 I, 3 + 3 I},
PlotLabel -> f[z], Contours -> {Range[-2, 2]},
ContourLabels -> All]} // Grid[{#}, Frame -> True] &
The result:
Also you could look into the modulus and argument of Exp[z]
. Perhaps this shows more clearly the mapping:
{ComplexContourPlot[AbsArg[z], {z, -3 - 3 I, 3 + 3 I}, PlotLabel -> z,
Contours -> {Range[-3, 3]}, ContourLabels -> All],
ComplexContourPlot[AbsArg[f[z]], {z, -3 - 3 I, 3 + 3 I},
PlotLabel -> f[z], Contours -> {Range[-3, 3]},
ContourLabels -> All]} // Grid[{#}, Frame -> True] &
Here you can see that circles in z
plane (Abs[z]
constant) are mapped into real lines Exp[x+Iy] (* Exp[x] is constant *)
, and that lines through the origin in the z
plane (Arg[z]
constant) are mapped into Exp[x+Iy] (* y is constant*)
lines.
Correct answer by Ferca on December 18, 2020
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