Mathematica Asked on June 4, 2021
I’m currently optimising my code and I’m using a lot of loops, so I was wondering if there is a smarter or faster way to do things like:
Do[If[MemberQ[List1[[II]], List2_], AppendTo[Newlist1, List1[[II]]]], {II, Length[List1]}]
I guess using Apply
would be better, but since I’m not primary a programmer I would be happy for any help. Thank you!
First question: select those elements in list1
that also appear in list2
:
list1 = {a, b, c, d, e, f};
list2 = {e, g, i};
Select[list1, MemberQ[list2, #] &]
(* {e} *)
Second question: select those elements in list1
that have a factor that is in list2
:
list1 = {a b c d, x y z, m n o};
list2 = {a, r, l, m};
Select[list1, IntersectingQ[List @@ #, list2] &]
(* {a b c d, m n o} *)
Correct answer by Roman on June 4, 2021
Try the following, first remove from the first list the elements of the second one:
lst1 = {a, b, c, d, e, f, g};
lst2 = {b, c, g};
Complement[lst1, lst2]
(* {a, d, e, f} *)
and then append it to the newList.
Clear[newList];
newList = {AA, BB, CC}; (*This is the initial newList*)
AppendTo[newList, Complement[lst1, lst2]] // Flatten
(* {AA, BB, CC, a, d, e, f} *)
Have fun!
Answered by Alexei Boulbitch on June 4, 2021
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