Mathematica Asked on May 14, 2021
If I have the following data:
data= {{-2., 0.147789}, {-1.52288, 0.237749}, {-1., 0.476084}, {-0.522879,
0.641128}, {-4.82164*10^-17, 1.04976}, {0.477121, 1.43399}, {1.,
1.77276}, {1.47712, 2.23469}, {2., 2.46328}, {2.47712,
2.85828}, {3., 2.96392}, {3.47712, 2.91354}, {4., 3.02119}}
which plotted as:
ListPlot[data, PlotRange -> All, AspectRatio -> 1 , Frame -> True, Axes -> False, AspectRatio -> 1, FrameStyle -> Directive[Black, 13], FrameLabel -> {Style["Log t(s)", 16], Style["!(*SubscriptBox[([CapitalDelta]H), (a)])(!(*SuperscriptBox[(Jg), (-1)]))", 16]}]
gives:
Questions:
Where ΔHa (ta)
is what I am plotting in the y-axis, t
is what I am plotting in the x axis (notice that time is in Log10 scale in the x-axis of the plot) and τ0
and β
are the best fitting parameters of the equation. ΔHa(∞)
is simply the average of the last three data calculated as DHinfinity = Mean[{3.02119, 2.91354, 2.96392}]
τ0
and β
?Clear["Global`*"]
data = {{-2., 0.147789}, {-1.52288, 0.237749}, {-1.,
0.476084}, {-0.522879, 0.641128}, {-4.82164*10^-17,
1.04976}, {0.477121, 1.43399}, {1., 1.77276}, {1.47712,
2.23469}, {2., 2.46328}, {2.47712, 2.85828}, {3.,
2.96392}, {3.47712, 2.91354}, {4., 3.02119}};
{logtmin, logtmax} = MinMax[data[[All, 1]]]
(* {-2., 4.} *)
DHinfinity = Mean[data[[All, 2]][[-3 ;;]]]
(* 2.96622 *)
EDIT: Corrected model to use Log10[t]
vice Log[t]
. This does not change the fit, merely the parameter values. Also added constraint that 0 < b < 1
(unnecessary in this particular case)
(nlm = NonlinearModelFit[
data, {DHinfinity (1 - Exp[-(10^logt/tau)^b]), 0 < b < 1}, {tau, b},
logt]) // Normal
(* 2.96622 (1 - E^(-0.40494 (10^logt)^0.356033)) *)
nlm["BestFitParameters"]
(* {tau -> 12.6687, b -> 0.356033} *)
Plot[nlm[logt], {logt, logtmin, logtmax},
PlotRange -> All,
AspectRatio -> 1,
Frame -> True,
Axes -> False,
AspectRatio -> 1,
FrameStyle -> Directive[Black, 13],
FrameLabel -> {Style[StringForm["`` t (s)", Subscript[Log, 10]], 16],
Style["!(*SubscriptBox[(ΔH),
(a)])(!(*SuperscriptBox[(Jg), (-1)]))", 16]},
Epilog -> {Red, AbsolutePointSize[4], Point[data]}]
Correct answer by Bob Hanlon on May 14, 2021
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