Mathematica Asked by Real Noob on December 22, 2020
I have an expression for which I want ot find values of n that will make it an integer. Here is the expression:
(n^(3/2) - n)^(1/3)
or
n^(1/2) - n^(1/3)
I want to find all positive values of n for which the above expression will be an Integer. Can I do that with Mathematica?
Thanks.
Using InverseFunction
f := Evaluate@InverseFunction[(#^(3/2) - #)^(1/3) &]
a = N[f /@ Range[3]]
{2.1479, 5.73535, 11.3776}
The above values will produce integers, e.g.
(#^(3/2) - #)^(1/3) & /@ a
{1., 2., 3.}
Correct answer by Chris Degnen on December 22, 2020
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